What volume in dm3 of KCl is obtained in the following equation if the volume of KCIO3 at the beginning of the reaction is 20 dm3? 2KClO3 → 2KCl + 3O2
Correct answer: E. 20 dm3
- A. 2 dm3
- B. 74.5 dm3
- C. 50 dm3
- D. 40 dm3
- E. 20 dm3
Explanation
To determine the volume of KCl obtained in the given equation, we need to know the stoichiometric ratio between KCIO3 and KCl. From the balanced equation: 2KClO3 → 2KCl + 3O2 We can see that for every 2 moles of KCIO3, we obtain 2 moles of KCl. Therefore, the ratio is 1:1. Given that the volume of KCIO3 at the beginning of the reaction is 20 dm3, and the stoichiometric ratio is 1:1, the volume of KCl obtained will also be 20 dm3. Therefore, the volume of KCl obtained in the given equation is 20 dm3.
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