The chemical analysis of a compound having a molecular mass 188 gives, C=12.8%, H=2.1%, and Br=85.1%. Its molecular formula is:
Correct answer: B. C2H4Br2
- A. CH2Br
- B. C2H4Br2
- C. C2H4Br
- D. CH2(Br)2
- E. C2H2(Br)3
Explanation
To determine the molecular formula, first calculate the empirical formula based on the given percentage composition:Convert the percentage of each element to mass: 12.8 g of C, 2.1 g of H, and 85.1 g of Br.Convert mass to moles: C (12.8 g / 12.01 g/mol), H (2.1 g / 1.008 g/mol), Br (85.1 g / 79.904 g/mol).Find the mole ratio by dividing each by the smallest number of moles.The empirical formula is CH2Br.The empirical formula mass is approximately 94.5 g/mol.Divide the molecular mass (188 g/mol) by the empirical formula mass (94.5 g/mol) to find the multiplier, which is 2.Multiply the empirical formula by this factor to get the molecular formula: C2H4Br2.Options A, C, D, and E do not match the molecular mass or fail to maintain the correct elemental ratio.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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