106g of Na2CO3 per dm3 of the solution of Na2CO3 in water, the concentration of the solution will be:
Correct answer: C. 1 M
- A. 2 M
- B. 0.1 M
- C. 1 M
- D. 0.02 M
Explanation
Na2CO3 = 23(2)+12+16(3) = 46+12+48 = 106 Concentration = Given mass/molar mass Concentration = 106/106 = 1M.
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