If we take 2.2g of CO2, 6.02 x 10^21 atoms of nitrogen and 0.03g atoms of sulfur, then the molar ratio of CO2, N and S atoms will be:
Correct answer: D. 5:1:3
- A. 1:2:5
- B. 5:1:2
- C. 2:5:3
- D. 5:1:3
Explanation
We have to calculate moles for each of the elements givenFor CO2 mass if given so use the formulamoles = mass/mr (Mr = 12 + 32 = 44)moles = 2.2/44 moles = 0.05Nitrogen atoms are given so using the formulaatoms = moles x avogadros constantmoles = atoms/ avogadros constant moles = 6.02 x1021 / 6.02x1023moles = 0.01For sulfur, gram atoms are given and gram atoms = molesSo, moles = 0.03Now calculating the molar ratioCO2 : N : S0.05 : 0.01 : 0.03 (Multiply by 100 to convert to whole numbers ratios already in lowest form)5 : 1 : 3 This is the following solution:
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About Fundamental Concepts of Chemistry
Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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