Asked in ETEA MDCAT 2017 2017Moderate

What type of hybridization is/are present in Hex-4-ene 1-yne:

Correct answer: D. Sp. Sp2. Sp3

  • A. Sp2
  • B. Sp
  • C. Sp and Sp2
  • D. Sp. Sp2. Sp3

Explanation

The first carbon atom has an sp hybridization, as it is involved in a triple bond with another carbon atom.The second and third carbon atoms have sp2 hybridization, as they are involved in a double bond with a carbon atom and a single bond with two other carbon atoms.The fourth carbon atom has sp hybridization, as it is involved in a triple bond with a carbon atom.The fifth carbon atom has sp2 hybridization, as it is involved in a double bond with a carbon atom and a single bond with two other carbon atoms.The sixth carbon atom has sp3 hybridization, as it is bonded to two other carbon atoms and two hydrogen atoms, resulting in a tetrahedral geometry.Therefore, the correct answer is D) sp, sp2, sp, sp2, sp, sp3. Explanation is given below.

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About Hybridization

Hybridization explains bonding by combining atomic orbitals to form equivalent hybrid orbitals with definite geometries. Coverage includes sp, sp², sp³, sp³d and sp³d² hybridization, their shapes and bond angles, and the relation of sigma and pi bonds to molecular structure.

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