What type of hybridization is/are present in Hex-4-ene 1-yne:
Correct answer: D. Sp. Sp2. Sp3
- A. Sp2
- B. Sp
- C. Sp and Sp2
- D. Sp. Sp2. Sp3
Explanation
The first carbon atom has an sp hybridization, as it is involved in a triple bond with another carbon atom.The second and third carbon atoms have sp2 hybridization, as they are involved in a double bond with a carbon atom and a single bond with two other carbon atoms.The fourth carbon atom has sp hybridization, as it is involved in a triple bond with a carbon atom.The fifth carbon atom has sp2 hybridization, as it is involved in a double bond with a carbon atom and a single bond with two other carbon atoms.The sixth carbon atom has sp3 hybridization, as it is bonded to two other carbon atoms and two hydrogen atoms, resulting in a tetrahedral geometry.Therefore, the correct answer is D) sp, sp2, sp, sp2, sp, sp3. Explanation is given below.
This question appeared on the ETEA MDCAT 2017 paper, which you can sit online with every answer explained.
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About Hybridization
Hybridization explains bonding by combining atomic orbitals to form equivalent hybrid orbitals with definite geometries. Coverage includes sp, sp², sp³, sp³d and sp³d² hybridization, their shapes and bond angles, and the relation of sigma and pi bonds to molecular structure.
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