Asked in ETEA MDCAT 2015 2015Moderate

Choose the type of hybridization of carbon atoms in cyclopropane and the bond angle C-C-C.

Correct answer: B. Sp3, 60*

  • A. Sp3, 109.5*
  • B. Sp3, 60*
  • C. Sp2, 120*
  • D. Sp2, 107*

Explanation

Cyclopropane has carbons with four bonds, hence they are SP3, but with bond distances less than normal alkanes and C-C-C bond angles of 60 degrees and H-C-H angles of 120 degrees. They are a special case as usually SP3 hybridization displays 109.5-degree angles

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Hybridization explains bonding by combining atomic orbitals to form equivalent hybrid orbitals with definite geometries. Coverage includes sp, sp², sp³, sp³d and sp³d² hybridization, their shapes and bond angles, and the relation of sigma and pi bonds to molecular structure.

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