Free Hybridization MCQs with Answers

61 Hybridization MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

Hybridization explains bonding by combining atomic orbitals to form equivalent hybrid orbitals with definite geometries. Coverage includes sp, sp², sp³, sp³d and sp³d² hybridization, their shapes and bond angles, and the relation of sigma and pi bonds to molecular structure.

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61 questions · page 1 of 4

Moderate
  • A. sp
  • B. sp2
  • C. sp3
  • D. sp3d

Explanation: One 2s and three 2p orbitals mix to give four equivalent sp3 hybrids directed to the corners of a tetrahedron, which explains why all four…

Correct answer: sp3
  • A. 25 per cent
  • B. 33.3 per cent
  • C. 50 per cent
  • D. 100 per cent

Explanation: An sp2 hybrid is formed from one s and two p orbitals, so the s contribution is one in three.

Correct answer: 33.3 per cent
  • A. sp3, with the lone pair occupying one of the four hybrid orbitals
  • B. sp2
  • C. sp
  • D. unhybridised

Explanation: Nitrogen has four regions of electron density, three bonds and one lone pair, so four sp3 hybrids are needed even though only three of…

Correct answer: sp3, with the lone pair occupying one of the four hybrid orbitals
  • A. sp3
  • B. sp2
  • C. sp
  • D. unhybridised

Explanation: The carbon has only two regions of electron density, since each double bond counts as one region, so two sp hybrid orbitals point in…

Correct answer: sp
Moderate
  • A. 90 degrees
  • B. 109.5 degrees
  • C. 120 degrees
  • D. 180 degrees

Explanation: Four equivalent orbitals repel each other to the corners of a tetrahedron, which places them at 109.5 degrees.

Correct answer: 109.5 degrees
  • A. sp3
  • B. sp2
  • C. sp
  • D. a mixture of sp2 and sp3

Explanation: Each carbon forms three sigma bonds, two to neighbouring carbons and one to a hydrogen, using sp2 hybrids at 120 degrees, which makes the…

Correct answer: sp2
  • A. sp > sp2 > sp3
  • B. sp3 > sp > sp2
  • C. sp2 > sp > sp3
  • D. sp3 > sp2 > sp

Explanation: The greater the s character, the closer the orbital is held to the nucleus and the smaller it is, and s character rises from 25 per cent…

Correct answer: sp3 > sp2 > sp
  • A. sp hybridised carbon atoms only
  • B. sp3 hybridised carbon atoms only
  • C. both sp and sp2 hybridised carbon atoms
  • D. both sp and sp3 hybridised carbon atoms
  • E. All types of carbons with sp,sp2,Sp3

Explanation: The structure of 2-butyne is CH3-C≡C-CH3. The two carbons in the triple bond are sp hybridised, while the two methyl carbons form four…

Correct answer: both sp and sp3 hybridised carbon atoms
  • A. Sp3 hybrid having 8 electrons
  • B. Sp2 hybrid having 6 electron
  • C. sp2 hybrid having 7 electron
  • D. Sp hybrid having linear geometry

Explanation: A methyl radical, CH3·, has three sigma bonds and one unpaired electron, so its carbon is approximately sp2 hybridized with trigonal…

Correct answer: sp2 hybrid having 7 electron
  • A. Sp
  • B. Sp2
  • C. Sp3
  • D. It is not hybridized

Explanation: The nitrogen atom in pyridine is sp2 hybridized because it forms three sp2-based sigma bonds in a planar aromatic ring, while its…

Correct answer: Sp2
  • A. Sp2
  • B. Sp3
  • C. Sp
  • D. dsp2

Explanation: In BeCl2, beryllium forms two sigma bonds and has no lone pair on the central atom, giving two electron domains.

Correct answer: Sp
  • A. 115.5°
  • B. 109.5°
  • C. 105. 7°
  • D. 180°

Explanation: In methane, each carbon atom is sp3 hybridised and the four bonding orbitals point towards the corners of a tetrahedron.

Correct answer: 109.5°
  • A. All p-orbitals are involved
  • B. One s and 3 p-orbitals are involved
  • C. one p-orbital is involved
  • D. four p-orbitals are involved

Explanation: In sp3 hybridization, one s orbital mixes with three p orbitals of the same shell to form four equivalent sp3 hybrid orbitals.

Correct answer: One s and 3 p-orbitals are involved
  • A. Triangular
  • B. Tetrahedral
  • C. Square planner
  • D. Linear

Explanation: sp3 hybridization produces four equivalent hybrid orbitals directed toward the corners of a tetrahedron, giving tetrahedral geometry in a…

Correct answer: Tetrahedral
  • A. 2n
  • B. n
  • C. 3n
  • D. impossible to predict

Explanation: When n atomic orbitals mix, they produce n hybrid orbitals because orbital mixing conserves the total number of orbitals.

Correct answer: n
  • A. sp3
  • B. sp2
  • C. sp
  • D. All

Explanation: In O2, each oxygen is commonly described as sp2 hybridized: two sp2 orbitals form sigma bonds or hold lone pairs, while an unhybridized p…

Correct answer: sp2
  • A. sp2
  • B. sp
  • C. sp3
  • D. none of the above

Explanation: In a cyano group, the carbon is bonded through a triple bond, which requires one sigma bond and two pi bonds.

Correct answer: sp
  • A. square planar
  • B. trigonal pyramidal
  • C. tetrahedral
  • D. linear

Explanation: sp3 hybridization produces four equivalent hybrid orbitals directed toward the corners of a tetrahedron, giving a tetrahedral…

Correct answer: tetrahedral
  • A. Sp
  • B. Sp2
  • C. Sp3
  • D. Dsp

Explanation: Linear-shaped hybrid orbitals are formed by the combination of one s orbital and one p orbital.

Correct answer: Sp
  • A. sp3
  • B. dsp2
  • C. d2 sp3
  • D. dsp3

Explanation: d2sp3 is correct because it corresponds to the hybridization of Pt in the square planar complex [Pt(NH3)4]2+.

Correct answer: d2 sp3

Hybridization MCQs: common questions

Are these Hybridization MCQs free?

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There are 61 Hybridization MCQs in the Chemistry bank, shown 20 to a page with the correct answer and an explanation on each.

Does every Hybridization MCQ have an explanation?

Yes. Each Hybridization question shows the correct option and a written explanation of why it is correct, so a wrong answer teaches you something rather than just being marked wrong.

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