What is the concentration of nitrate ions? If equal volumes of 0.1M AgnO3 and 0.1 MNaCl are mixed together?

Explanation

When equal volumes of 0.1 M AgNO3 and 0.1 M NaCl are mixed, the following reaction occurs:AgNO3 (aq) + NaCl (aq) -> AgCl (s) + NaNO3 (aq)In this reaction, each mole of AgNO3 reacts with one mole of NaCl to produce one mole of AgCl and one mole of NaNO3. Since the initial concentrations of AgNO3 and NaCl are equal (0.1 M), their moles will also be equal.Concentration of Nitrate Ions (NO3-) in the Final Mixture:WaInitial Concentration of NO3-: There is initially NO3- in the NaCl solution. In the AgNO3 solution, the concentration of NO3- is the same as the concentration of AgNO3, which is 0.1 M.Change in Concentration due to Reaction: Since each mole of AgNO3 reacts to produce one mole of NaNO3, the final concentration of NO3- in the mixture will be the same as the initial concentration of AgNO3.Final Concentration of NO3-: As mentioned in step 1, the initial concentration of AgNO3 (and therefore NO3-) was 0.1 M. However, when the solutions are mixed, the volume doubles. So, the final concentration of NO3- is:Final concentration of NO3- = (Initial concentration of NO3-) * (Initial volume) / (Final volume) = 0.1 M * 1 L / 2 L = 0.05 MTherefore, the correct concentration of nitrate ions (NO3-) in the final mixture is 0.05 M.