Kinetic energy of one mole of an ideal gas at 300K in kj is
Correct answer: C. 3.74
- A. 34.8
- B. 3.48
- C. 3.74
- D. 348
Explanation
We can calculate the kinetic energy (KE) of one mole of an ideal gas using the formula:KE = (3/2) * R * Twhere:KE is the kinetic energy in Joules (J)R is the universal gas constant (8.314 J/mol*K)T is the absolute temperature in Kelvin (K)Given:T = 300 KSubstituting the values:KE = (3/2) * 8.314 J/mol*K * 300 K ≈ 3741.3 JConverting Joules to kilojoules:KE ≈ 3741.3 J / 1000 J/kJ ≈ 3.74 kJTherefore, the kinetic energy of one mole of an ideal gas at 300 K is approximately 3.74 kJ
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