Kinetic energy of one mole of an ideal gas at 300K in kj is
Correct answer: C. 3.74
- A. 34.8
- B. 3.48
- C. 3.74
- D. 348
Explanation
We can calculate the kinetic energy (KE) of one mole of an ideal gas using the formula:KE = (3/2) * R * Twhere:KE is the kinetic energy in Joules (J)R is the universal gas constant (8.314 J/mol*K)T is the absolute temperature in Kelvin (K)Given:T = 300 KSubstituting the values:KE = (3/2) * 8.314 J/mol*K * 300 K ≈ 3741.3 JConverting Joules to kilojoules:KE ≈ 3741.3 J / 1000 J/kJ ≈ 3.74 kJTherefore, the kinetic energy of one mole of an ideal gas at 300 K is approximately 3.74 kJ
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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