In which gaseous equilibrium more product will be formed by decreasing pressure
Correct answer: C. 2SO2 + O2 ⇌ 2SO3
- A. N2+3H2 ⇌ 2NH3
- B. PCl5 ⇌PCl3 +Cl2
- C. 2SO2 + O2 ⇌ 2SO3
- D. 2H2 + O2 ⇌ 2H2O
Explanation
According to Le Chatelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tries to minimize the effect of that stress. In this case, decreasing pressure acts as a stress.Number of moles: In the given options:A, B, and D have the same number of moles on both sides (reactants and products).Only C has fewer moles on the product side (2) compared to the reactant side (3).Pressure change: When pressure decreases, the system tries to shift the equilibrium in the direction that will decrease the total number of gas molecules. Since C has fewer moles on the product side, shifting the equilibrium to the right (towards products) will decrease the total number of gas molecules, counteracting the decrease in pressure.Therefore, in C) 2SO2 + O2 ⇌ 2SO3, decreasing pressure will drive the equilibrium towards the formation of more product (SO3).
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