What is the charge stored on a 5 μF capacitor charged to a potential difference of 12 V?
Correct answer: A. 60 μC
- A. 60 μC
- B. 2.4 C
- C. 2.4 μC
- D. 60 C
Explanation
Use formula Q=CV, where C is .005 F and V is 12 V, and then convert the answer to μC by dividing it with 1000.0.005 x 12 / 1000 = 60 μC.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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