The difference between the plates of a parallel plate capacitor is 2.0 mm and the area of each plate is 2.0 m2. The plates are in a vacuum. A potential difference of 1.0 x 10^4 V is applied across the plates. Find the capacitance.
Correct answer: C. 8.85 x 10^-9 F
- A. 4.0 x 10^-3 F
- B. 3.54 x 10^-9 F
- C. 8.85 x 10^-9 F
- D. 9.0 x 10^-9 F
Explanation
The capacitance of a parallel plate capacitor isC=ЄA/dC=(8.85x10^-12)x(2)/(2x10^-3)=8.85 x 10^-9CAs it is numerical, it can have only one possible answer.
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