10 V potential difference is applied across the plate of the 1 µF capacitor. What is the energy stored in the capacitor?
Correct answer: B. 0.05 mJ
- A. 0.5 mJ
- B. 0.05 mJ
- C. 5 mJ
- D. 50 mJ
Explanation
The energy stored in a capacitor can be calculated using the formula:E = (1/2) * C * V2Where,E is the energy storedC is the capacitanceV is the potential difference applied across the capacitor.Substituting the given values into the formula, we get:E = (1/2) * 1 uF * (10 V)2Since 1 uF = 10-6 F, we can rewrite the expression as:E = (1/2) * 10-6 F * (10 V)2Simplifying the expression, we get:E = 0.5 * 10-6 * 100E = 0.05 * 10-3 JE = 0.05 mJTherefore, the energy stored in the capacitor is 0.05 mJ. Hence, option (B) is correct.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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