10 V potential difference is applied across the plate of the 1 µF capacitor. What is the energy stored in the capacitor?
Correct answer: B. 0.05 mJ
- A. 0.5 mJ
- B. 0.05 mJ
- C. 5 mJ
- D. 50 mJ
Explanation
The energy stored in a capacitor can be calculated using the formula:E = (1/2) * C * V2Where,E is the energy storedC is the capacitanceV is the potential difference applied across the capacitor.Substituting the given values into the formula, we get:E = (1/2) * 1 uF * (10 V)2Since 1 uF = 10-6 F, we can rewrite the expression as:E = (1/2) * 10-6 F * (10 V)2Simplifying the expression, we get:E = 0.5 * 10-6 * 100E = 0.05 * 10-3 JE = 0.05 mJTherefore, the energy stored in the capacitor is 0.05 mJ. Hence, option (B) is correct.
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