What is the magnitude of a point charge which produces an electric field of 2 N/C at a distance of 60 cm?
Correct answer: A. 8 × 10−11C
- A. 8 × 10−11C
- B. 2 × 10−12C
- C. 3 × 10−11C
- D. 6 × 10−10C
Explanation
The electric field (E) due to a point charge (q) at a distance (r) is given by the formula E = k * |q| / r2, where k is the electrostatic constant (approximately 8.99 × 109 N m2/C2). Here, E = 2 N/C and r = 60 cm = 0.6 m. Rearranging the formula to solve for |q|, we have |q| = E * r2 / k. Substituting the values, |q| = (2 N/C) * (0.6 m)2 / (8.99 × 109 N m2/C2) = 8 × 10−11C. Therefore, the correct answer is 8 × 10−11C. The other options fail to provide the correct magnitude as they either miscalculate or misinterpret the formula and given values.
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