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Two persons A and B take a field on rent. A puts on it 21 horses for 3 months and 15 cows for 2 months; B puts 15 cows for 6months and 40 sheep for 7 1/2 months. If one day, 3 horses eat as much as 5 cows and 6 cows as much as 10 sheep, what part of the rent should A pay?

Correct answer: A. 1/3 rd

  • A. 1/3 rd
  • B. 2/5 th
  • C. 2/3 rd
  • D. 1/5 th

Explanation

Using cows as the common unit, 3 horses = 5 cows, so A contributes 21 x 3 x 5/3 = 105 cow-months from horses and 15 x 2 = 30 cow-months from cows, total 135 cow-months. Also, 6 cows = 10 sheep, so 40 sheep x 7.5 months x 6/10 = 180 cow-months; B's total is 15 x 6 + 180 = 270 cow-months. A pays 135/(135 + 270) = 1/3 of the rent. The likely mistake is option b, 2/5, caused by using the animal counts directly without converting them to equivalent feeding units.

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