Three 6 faced dice are thrown together. The probability that no two dice show the same number on them is__________?
Correct answer: B. 5/9
- A. 7/12
- B. 5/9
- C. 1/36
- D. 5/12
Explanation
For three different results, the first die has 6 choices, the second 5 remaining choices, and the third 4 remaining choices. Hence the probability is (6 x 5 x 4)/6^3 = 120/216 = 5/9. Students may choose 7/12 by confusing the event with the probability that some pair is equal.
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