The volume occupied by 16g of oxygen at STP is:
Correct answer: C. 11.2dm3
- A. 2.24dm3
- B. 22.4dm3
- C. 11.2dm3
- D. 1.24dm3
Explanation
According to Avogadro's Law and the molar mass of oxygen (O₂), which is approximately 32 g/mol, 1 mole of oxygen gas occupies 22.4 dm³ at STP. Since we have 16 g of oxygen, which is half of the molar mass, we would have half a mole of oxygen gas, occupying half the volume, which is 11.2 dm³. Therefore, the correct answer is 11.02dm3.
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