24g each of carbon and oxygen react to form CO2. The amount of unreacted element left behind is:
Correct answer: B. 15g
- A. 6g
- B. 15g
- C. 16g
- D. 10g
Explanation
1 mole combines with 1 mole of O2 to give 1 Mole of CO2.No of moles of C in 24 g = 24/12 =2 molesNo of moles of O2 in 24 g = 24/32 = 0.75 molesSince the number of moles of O2 is only 0.75 so it can react with only 0.75 moles of C, and the rest of the C will remain unreacted.Mass of 0.75 moles of C = 12 g/mol x 0.75 mol = 9gUnreacted element left behind = 24-9 =15g
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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