From the complete decomposition of 0.2 moles CaCO3 at S.T.P. the volume of CO2 obtained is:
Correct answer: B. 4.48 L.
- A. 2.24 L.
- B. 4.48 L.
- C. 44.8 L.
- D. 48.4 L.
Explanation
Chemical reaction involved is: CaCO3 _CaO + CO2 As the reaction is balanced so 0.2 moles of calcium carbonate will produce 0.2 moles of CO2 Molar volume at S.T.P is 22.414dm3 Now No. of moles= volume/molar volume By rearranging Volume of CO2= molar volume * no. of moles =22.414dm3*0.2 =4.48L So the correct answer is B.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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