Largest number of molecules is present in:
Correct answer: C. 8.00g H2
- A. 32.0g O2
- B. 44.0g CO2
- C. 8.00g H2
- D. 56.0g N2
Explanation
Molar mass of H2 = 2 x 1.01 g/mol = 2.02 g/molMoles of H2 = Mass (g) / Molar mass (g/mol)Moles of H2 =8.00 g / 2.02 g/mol = 4 molNo. of molecules= moles x NA= 4 x 6.02 x1023 Hence, this is the correct answer.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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