Asked in ETEA MDCAT 2009 2009Moderate

The speed of particle at the end of four successes seconds is 20,25,30, 35km/hr, the acceleration of the particle is:

Correct answer: A. 5km/hr²

  • A. 5km/hr²
  • B. 5km/sec²
  • C. 5km_hr/sec
  • D. 5km/hr_sec

Explanation

The acceleration of the particle cannot be determined with the given information. Acceleration is defined as the rate of change of velocity with respect to time. The formula for acceleration is: a = (v₂ - v₁) / (t₂ - t₁) where: a is the acceleration v₂ and v₁ are the final and initial velocities, respectively t₂ and t₁ are the final and initial times, respectively In this case, we are given the final velocities of the particle after four successive seconds as 20, 25, 30, and 35 km/hr, but we do not have the initial velocities or the times at which these velocities were measured. Therefore, we cannot calculate the acceleration of the particle using the above formula. Option (a) is incorrect because it represents acceleration in units of km/hr², which is not a standard unit of acceleration. The SI unit of acceleration is m/s². Therefore, the correct answer is that the acceleration of the particle cannot be determined with the given information.

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Acceleration measures the rate at which velocity changes with time, including changes in speed, direction or both. Work includes average and instantaneous acceleration, the relation a = Δv/Δt, uniform acceleration equations, and interpreting velocity time and displacement time graphs, with acceleration carefully distinguished from velocity.

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