The distance travelled by a moving car with velocity 15m/s in 2s, decelerates at 2m/s2 is equal to:
Correct answer: D. 26m
- A. 30m
- B. 16m
- C. 34m
- D. 26m
Explanation
This is a question from a body moving at constant acceleration for that we have 3 equations of motion vf=vi + at S=vit +1/2at2 2aS=vf2 - vi2 Here S refers to a displacement Vi is the initial velocity Vf is the final velocity t is for time a is for acceleration According to the data given, the most suitable equation to be used here is the 2nd equation of motion, SOL: S=vit+1/2at2 =15x2+½x(-2)22 -ve sign indicates that the car is decelerating =30-4 =26m Hence the correct answer is option D.
This question appeared on the UHS MDCAT 2017 paper, which you can sit online with every answer explained.
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About Acceleration
Acceleration measures the rate at which velocity changes with time, including changes in speed, direction or both. Work includes average and instantaneous acceleration, the relation a = Δv/Δt, uniform acceleration equations, and interpreting velocity time and displacement time graphs, with acceleration carefully distinguished from velocity.
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