Asked in ETEA MDCAT 2005 2005Moderate

A particle moves along a straight line. The distance × described in time t is given by the equation x= t3 volts. The acceleration at t=1 is initial velocity =c:

Correct answer: A. A=1

  • A. A=1
  • B. B=2
  • C. C=3
  • D. D=4

Explanation

They just made the question confusing In fact it's very simple We have to find the velocity Distance is given as x=t³ Where t=1 So x=1 We know velocity is x/t Putting x=1 And t=1 We get velocity as 1 Which is option A

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About Acceleration

Acceleration measures the rate at which velocity changes with time, including changes in speed, direction or both. Work includes average and instantaneous acceleration, the relation a = Δv/Δt, uniform acceleration equations, and interpreting velocity time and displacement time graphs, with acceleration carefully distinguished from velocity.

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