A ball is thrown vertically upward with a velocity of 98 m/s. if it takes 10 seconds to reach the highest point then the acceleration of the ball is:
Correct answer: D. -9.8 m/s
- A. 9.8 m/s²
- B. 980 m/s
- C. 98 m/s²
- D. -9.8 m/s
Explanation
Using the first equation of motion: v = u + at final velocity(v) =0m/s initial velocity (u) =98m/s time (t) = 10 acceleration (a) = ? 0=98+10a -98=10a a=-9.8m/s²
This question appeared on the ETEA MDCAT 2011 paper, which you can sit online with every answer explained.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Acceleration
Acceleration measures the rate at which velocity changes with time, including changes in speed, direction or both. Work includes average and instantaneous acceleration, the relation a = Δv/Δt, uniform acceleration equations, and interpreting velocity time and displacement time graphs, with acceleration carefully distinguished from velocity.
Practise Force and Motion
1,416 free Force and Motion MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Acceleration questions
The speed of particle at the end of four successes seconds is 20,25,30, 35km/hr, the acceleration of the particle is:
A force of 2000 dynes is applied to a mass of 250gm. What acceleration would be obtained?
A particle moves along a straight line. The distance × described in time t is given by the equation x= t3 volts. The acceleration at t=1 is initial velocity =c:
A ball of mass 5 kg is dropped from a height of 78.4 m. The time taken by the ball to hit the ground is:
A person travels a distance x = 20t+2At2, where A is a constant. The acceleration of the person is:
When released from a height a ball falls 5m in 1s. In 4s after release the ball will fall: