The middle term/s in the expansion of (a - 3x)^14 are:
Correct answer: B. T8
- A. T7
- B. T8
- C. T6 & T7
- D. T7 & T8
Explanation
Since the exponent n = 14, which is an even number, the middle term will be a single term.The middle term in the expansion of (a - 3x)^n, where n is even, is the term where the index r = n/2 + 1.In this case, with n = 14, the middle term will be:T8 = (14 choose 8) a^(14-8) (-3x)^8
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