The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:
Correct answer: C. 23
- A. 3
- B. 13
- C. 23
- D. 33
Explanation
The required sum must be divisible by LCM(5, 6, 4, 3) = 60. Since 2497 = 60 x 41 + 37, the least addition is 60 - 37 = 23, giving 2520, which is divisible by all four numbers. The likely mistake is choosing 3 by checking divisibility by 5 alone rather than by their common multiple.
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