The average age of M boys is 'b' years and of 'n' girls 'c' years. The average age of all together is_________?
Correct answer: C. (mb + nc)/ (m + n) years
- A. (mb - nc)/ (m + n) years
- B. (mb + nc)/ (m - n) years
- C. (mb + nc)/ (m + n) years
- D. (mb - nc)/ (m - n) years
Explanation
The total age of the M boys is Mb years, and the total age of the n girls is nc years. Therefore, the combined total age is Mb + nc years and the number of people is m + n, giving a combined average of (mb + nc)/(m + n) years. The likely mistake is choosing option a by subtracting the girls' total instead of combining both groups.
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An average represents the total of a set of values divided by the number of values, and a weighted average gives different importance to different groups. Problems involve missing values, combined averages, replacement of observations, and changes in the average, so the total and count must be tracked separately.
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