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The areas of two similar triangles are 12 cm2 and 48SQ. cm .If the height of the smaller one is 2.1cm than the corresponding height of the bigger one is_________?

Correct answer: B. 4.2cm

  • A. 0.525cm
  • B. 4.2cm
  • C. 80%
  • D. 60%

Explanation

For similar triangles, areas are proportional to the squares of corresponding heights. Since 48 cm² ÷ 12 cm² = 4, the height ratio is √4 = 2, so the larger height is 2 × 2.1 cm = 4.2 cm. The likely trap is 0.525 cm, which divides by 4 instead of using the square-root relationship.

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Triangles and angles involve angle pairs, vertically opposite angles, parallel lines, triangle angle sums, exterior angles, congruence, similarity, and the Pythagorean theorem. Questions also test properties of isosceles and equilateral triangles, with similarity focusing on proportional sides while congruence requires identical size and shape.

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