Milk and water in two vessels A and B are in the ratio 4:3 and 2:3 respectively in what ratio the liquids in both the vessels should be mixed to obtain a new mixture in vessel C containing half milk and half water?
Correct answer: D. 7:5
- A. 1:1
- B. 1:3
- C. 1:2
- D. 7:5
Explanation
Vessel A contains 4/7 milk and vessel B contains 2/5 milk. If x litres from A and y litres from B are mixed to obtain half milk, then (4/7)x + (2/5)y = (x + y)/2, which simplifies to x/14 = y/10 and x:y = 7:5. The likely mistake is option a, 1:1, which gives a mixture containing more than half milk because vessel A is richer in milk.
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