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In measuring the sides of a rectangle errors of 5 % and 3 % in excess are made. The error percent in the calculates area is_________?

Correct answer: C. 8.15 %

  • A. 8. 35 %
  • B. 7.15 %
  • C. 8.15 %
  • D. 6. 25%

Explanation

If the original side lengths are L and W, the measured lengths become 1.05L and 1.03W. The measured area is therefore 1.05 × 1.03 = 1.0815 times the true area, giving an error of (1.0815 − 1) × 100% = 8.15%. A student may choose a, 8.35%, by adding the two percentage errors and multiplying them incorrectly.

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