If the time of flight of a projectile is 10 seconds. The range is 500m. The maximum height attained by it will be:
Correct answer: A. 125 m
- A. 125 m
- B. 50 m
- C. 100 m
- D. 150 m
Explanation
Given that the range is 500m and the time of flight is 10 seconds, we can calculate the maximum height attained by the projectile using the formula h = u²sin²θ/2g, which results in 125m. This is the correct answer as it aligns with the provided data and calculations. The other options are incorrect as they do not match the calculated maximum height based on the given values.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Force and Motion
Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
Practise Force and Motion
1,416 free Force and Motion MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Force and Motion questions
To improve the jumping record, the long jumper should jump at an angle of:
A 7.0 kg bowling ball experiences a net force of 5.0 N. Its acceleration will be:
A ball is thrown vertically upwards at 19.6 m/s. For its complete trip (up and back down to the starting position), its average speed is:
One fielder throws a ball and in 4 seconds it reaches to another player. So, the maximum height reached by the ball above the point of projection would be about:
Two bodies are projected with the same velocity. If one is projected at an angle of 30o and the other at an angle of 60o to the horizontal, the ratio of the maximum heights reached is:
Two balls are projected from the top of a tower of height 120 m, one with an initial upward velocity of 36 km/h and the other with an initial downward velocity of 36 km/h. The speed of each ball just before hitting the ground is: (take g = 10 m/s2 )