To improve the jumping record, the long jumper should jump at an angle of:
Correct answer: B. 45o
- A. 30°
- B. 45o
- C. 60o
- D. 90o
Explanation
In projectile motion, the range R of a projectile is given by the formula R = (u² * sin 2θ) / g, where u is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity. To maximize the range, the value of sin 2θ should be maximum, which is 1. This occurs when 2θ = 90°, hence θ = 45°. Therefore, an angle of 45° provides the largest possible range for a projectile. Angles lower than 45° reduce the vertical component too much, while angles greater than 45° reduce the horizontal component, both leading to a shorter range. Thus, option B is correct, while options A, C, and D do not provide the optimal angle for maximum range.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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