7.0 kg bowling ball experience a net force of 5.0N. What will be its acceleration?
Correct answer: C. 0.71 m/s²
- A. 7.0 m/s²
- B. 5.0 m/s²
- C. 0.71 m/s²
- D. 35.0 m/s²
Explanation
From F = ma ⇒ a = F/m = 5.0 / 7.0 ≈ 0.714 m/s², rounded to 0.71 m/s².
Last updated
Related questions
(1, 1, 1) . (2, 2, 2)
1st law of motion gives the definition of:
2nd law of motion measures which quantity?
A 0.2 kg rubber ball is dropped from the window of a building. It strikes the sidewalk below at 30m/s and rebounds up at 20m/s. The impulse on the ball during the collision is:
A 1.0 kg ball moving at 2.0m/s perpendicular to a wall rebounds from the wall at 1.5m/s. The change in the momentum of the ball is: