7.0 kg bowling ball experience a net force of 5.0N. What will be its acceleration?

Correct answer: C. 0.71 m/s²

  • A. 7.0 m/s²
  • B. 5.0 m/s²
  • C. 0.71 m/s²
  • D. 35.0 m/s²

Explanation

From F = ma ⇒ a = F/m = 5.0 / 7.0 ≈ 0.714 m/s², rounded to 0.71 m/s².

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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.

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