A 7.0 kg bowling ball experiences a net force of 5.0 N. Its acceleration will be:
Correct answer: D. 0.71 m/s2
- A. 35 m/s2
- B. 7.0 m/s2
- C. 5.0 m/s2
- D. 0.71 m/s2
Explanation
To determine the acceleration of the bowling ball, use Newton's second law of motion, which states that acceleration (a) is equal to the net force (F) acting on an object divided by the object's mass (m): a = F/m.Given that the net force (F) is 5.0 N and the mass (m) is 7.0 kg, substitute these values into the formula:a = 5.0 N / 7.0 kg = 0.714 m/s²Therefore, the correct acceleration is approximately 0.71 m/s², which corresponds to Option D.Options A, B, and C are incorrect because they result from miscalculations or misapplications of the formula. Option A (35 m/s²) results from multiplying rather than dividing. Option B (7.0 m/s²) treats the mass as acceleration without calculation. Option C (5.0 m/s²) uses the force directly as acceleration, ignoring the mass.
Last updated
About Force and Motion
Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
Practise Force and Motion
1,416 free Force and Motion MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
(1, 1, 1) . (2, 2, 2)
1st law of motion gives the definition of:
2nd law of motion measures which quantity?
7.0 kg bowling ball experience a net force of 5.0N. What will be its acceleration?
A 0.2 kg rubber ball is dropped from the window of a building. It strikes the sidewalk below at 30m/s and rebounds up at 20m/s. The impulse on the ball during the collision is: