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I. a2 + 8a + 16 = 0, II. b2 - 4b + 3 = 0 to solve both the equations to find the values of a and b?

Correct answer: A. If a < b

  • A. If a < b
  • B. If a ≤ b
  • C. If the relationship between a and b cannot be established
  • D. If a > b

Explanation

a² + 8a + 16 = (a + 4)², so a = -4. Also, b² - 4b + 3 = (b - 1)(b - 3), so b = 1 or 3; therefore a is less than either possible value of b. The likely mistake is choosing c because the two possible values of b were not checked.

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