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At an examination in which full marks were 500. A got 10% less than B, B got 25% more than C and C got 20% less than D. If A got 360 marks, what percentage of full marks was obtained by D?

Correct answer: C. 80%

  • A. 70%
  • B. 90%
  • C. 80%
  • D. 75%

Explanation

A got 90% of B, B got 125% of C, and C got 80% of D, so A = 0.90 x 1.25 x 0.80 x D = 0.90D. Since A = 360 marks, D = 360/0.90 = 400 marks, and D's percentage is 400/500 x 100% = 80%. The likely trap is 90%, which is A's percentage of D, not D's percentage of the full 500 marks.

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