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At an examination in which full marks were 500. A got 10% less than B, B got 25% more than C and C got 20% less than D. If A got 360 marks, what percentage of full marks was obtained by D?

Correct answer: C. 80%

  • A. 70%
  • B. 90%
  • C. 80%
  • D. 75%

Explanation

A got 90% of B, B got 125% of C, and C got 80% of D, so A = 0.90 x 1.25 x 0.80 x D = 0.90D. Since A = 360 marks, D = 360/0.90 = 400 marks, and D's percentage is 400/500 x 100% = 80%. The likely trap is 90%, which is A's percentage of D, not D's percentage of the full 500 marks.

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Percentages express a quantity as parts per hundred and support calculations involving increases, decreases, discounts, commissions, taxes, and successive changes. Questions require distinguishing percentage change from percentage points and identifying the original value when a final value and its percentage change are given.

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