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A person travels from x to y at a speed of 40Km/h and returns by increasing his speed 50%. What is his average speed for both the trips?

Correct answer: C. 48km/h

  • A. 36km/h
  • B. 45km/h
  • C. 48km/h
  • D. 50km/h

Explanation

For equal distances, average speed is total distance divided by total time, or 2uv/(u+v). The return speed is 40 km/h x 1.50 = 60 km/h, so average speed = 2 x 40 km/h x 60 km/h ÷ (40 km/h + 60 km/h) = 48 km/h. The likely mistake is option b, which takes the arithmetic mean of 40 km/h and 60 km/h even though the travel times are unequal.

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About Time, Speed and Distance

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