A path of uniform width turns the inside of a rectangular field 38m long and 32m wide. IF the path occupies 600 m2 than the width of the path is_______?
Correct answer: B. 5m
- A. 3m
- B. 5m
- C. 8.75m
- D. 10m
Explanation
If the path has width w metres inside the field, its area is 38 m × 32 m minus (38 − 2w) m × (32 − 2w) m. Setting this equal to 600 square metres gives 1216 − (1216 − 140w + 4w²) = 600, or w² − 35w + 150 = 0, so w = 5 m or 30 m; only 5 m fits inside the 32 m width. The likely mistake is accepting 30 m, the algebraic root that is physically impossible for an internal path.
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