A merchant has three different types of milk: 435 liters, 493 liters and 551 liters. Find the least number of casks of equal size required to store all the milk without mixing.
Correct answer: A. 51
- A. 51
- B. 61
- C. 47
- D. 45
Explanation
To minimise the number of equal casks, use the greatest common capacity: HCF(435 L, 493 L, 551 L) = 29 L. The casks required are 435 ÷ 29 = 15, 493 ÷ 29 = 17, and 551 ÷ 29 = 19, giving 15 + 17 + 19 = 51 casks. The likely mistake is option b, 61, from using a non-maximal common capacity.
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