A man rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. What is his average speed for the entire trip approximately?
Correct answer: D. 10.8 kmph
- A. 11.2 kmph
- B. 10 kmph
- C. 10.2 kmph
- D. 10.8 kmph
Explanation
Total distance is 10 km + 12 km = 22 km, while total time is 10/12 h + 12/10 h = 61/30 h. Therefore average speed is 22 km ÷ (61/30 h) = 660/61 km/h, approximately 10.8 km/h; 11.2 km/h is likely obtained by taking an inappropriate average of 12 km/h and 10 km/h.
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An average represents the total of a set of values divided by the number of values, and a weighted average gives different importance to different groups. Problems involve missing values, combined averages, replacement of observations, and changes in the average, so the total and count must be tracked separately.
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