Moderate

A current carrying coil is placed in a uniform magnetic field.The torque produced in this coil will be doubled when the

Correct answer: D. Area of coil is doubled.

  • A. Force in the magnetic field is doubled.
  • B. Length of coil is reduced to half.
  • C. Moment arm is reduced to half.
  • D. Area of coil is doubled.

Explanation

The torque (τ) on a current-carrying coil in a magnetic field is given by τ = n · I · A · B · sin(θ), where n is the number of turns, I is the current, A is the area, B is the magnetic field strength, and θ is the angle between the normal to the coil and the magnetic field. Doubling the area (A) will directly double the torque, making Option D correct.Option A is incorrect as doubling the force without changing other parameters does not necessarily double the torque. Option B is incorrect because reducing the length would decrease the area, thus reducing the torque. Option C is incorrect because reducing the moment arm decreases the torque.

Last updated

About Magnetic Flux Density

Magnetic flux density measures the magnetic force acting on a current carrying conductor or moving charge in a magnetic field. Work includes the relations B equals F divided by IL and F equals qvB, the tesla as its SI unit, field direction and the distinction between flux density and magnetic flux.

Practise Electromagnetism

1,176 free Electromagnetism MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Exams that ask Physics questions like this

Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

Related questions