A current carrying coil is placed in a uniform magnetic field.The torque produced in this coil will be doubled when the

Correct answer: D. Area of coil is doubled.

  • A. Force in the magnetic field is doubled.
  • B. Length of coil is reduced to half.
  • C. Moment arm is reduced to half.
  • D. Area of coil is doubled.

Explanation

The torque (τ) on a current-carrying coil in a magnetic field is given by τ = n · I · A · B · sin(θ), where n is the number of turns, I is the current, A is the area, B is the magnetic field strength, and θ is the angle between the normal to the coil and the magnetic field. Doubling the area (A) will directly double the torque, making Option D correct.Option A is incorrect as doubling the force without changing other parameters does not necessarily double the torque. Option B is incorrect because reducing the length would decrease the area, thus reducing the torque. Option C is incorrect because reducing the moment arm decreases the torque.

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About Magnetic Flux Density

Magnetic flux density measures the magnetic force acting on a current carrying conductor or moving charge in a magnetic field. Work includes the relations B equals F divided by IL and F equals qvB, the tesla as its SI unit, field direction and the distinction between flux density and magnetic flux.

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