If 9 A current is passing through a wire of length 1.5 m experiences a perpendicular magnetic force of 0.25 N, then the magnetic field is
Correct answer: A. 0.018 T
- A. 0.018 T
- B. 0.041 T
- C. 0.194 T
- D. 0.541 T
Explanation
To determine the magnetic field B, use the formula for the magnetic force on a current-carrying conductor: F = BIL. Rearrange the formula to solve for B, giving B = F/(IL). Substituting the given values: F = 0.25 N, I = 9 A, and L = 1.5 m, we find B = 0.25/(9 * 1.5) = 0.018 T. Therefore, the correct answer is 0.018 T. The other options are incorrect due to errors in calculation or misapplication of the formula.
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About Magnetic Flux Density
Magnetic flux density measures the magnetic force acting on a current carrying conductor or moving charge in a magnetic field. Work includes the relations B equals F divided by IL and F equals qvB, the tesla as its SI unit, field direction and the distinction between flux density and magnetic flux.
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