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If a 1 m metallic wire is placed perpendicularly in a uniform magnetic field of 0.10 T and carrying current of 10 A, then the force acting on the wire will be

Correct answer: B. 1 N.

  • A. 0.01 N.
  • B. 1 N.
  • C. 10 N.
  • D. 100 N.

Explanation

The force on a current-carrying conductor in a magnetic field is calculated using the formula F = B * I * L, where F is the force, B is the magnetic field strength (0.10 T), I is the current (10 A), and L is the length of the wire (1 m). Substituting these values gives F = 0.10 * 10 * 1 = 1 N. Other options result from incorrect calculations: 0.01 N is too low, 10 N and 100 N are too high.

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About Magnetic Flux Density

Magnetic flux density measures the magnetic force acting on a current carrying conductor or moving charge in a magnetic field. Work includes the relations B equals F divided by IL and F equals qvB, the tesla as its SI unit, field direction and the distinction between flux density and magnetic flux.

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