A metallic wire of length 1 m is placed perpendicular to a uniform magnetic field of 10 T.If this wire is carrying current of 100 A, then the force acting on this wire will be
Correct answer: D. 1000 N.
- A. 0 N.
- B. 10 N.
- C. 100 N.
- D. 1000 N.
Explanation
The force on a current-carrying wire in a magnetic field is calculated using the formula F = BILsinθ. In this case, the wire is perpendicular to the magnetic field (θ = 90°), so sinθ = 1. Substituting the given values into the formula: B = 10 T, I = 100 A, L = 1 m, results in F = 10 x 100 x 1 x 1 = 1000 N. Thus, option D (1000 N) is correct. Option A (0 N) is incorrect because there is a magnetic field and current present. Option B (10 N) and Option C (100 N) are incorrect due to miscalculations based on incorrect application of the formula.
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About Magnetic Flux Density
Magnetic flux density measures the magnetic force acting on a current carrying conductor or moving charge in a magnetic field. Work includes the relations B equals F divided by IL and F equals qvB, the tesla as its SI unit, field direction and the distinction between flux density and magnetic flux.
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