A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Correct answer: B. 200
- A. 150
- B. 200
- C. 250
- D. 300
Explanation
Choose 2 men from 5 and 3 women from 6: 5C2 x 6C3 = 10 x 20 = 200 ways. The likely trap is option a, 150, from using an incorrect value for 6C3 or forgetting that both selections must be made.
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