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18 cattle graze a field in 12 days. 6 cattle can graze 3 of such fields in x days. What is x?

Correct answer: D. 108

  • A. 90
  • B. 72
  • C. 36
  • D. 108

Explanation

One field requires 18 cattle x 12 days = 216 cattle-days, so 3 fields require 3 x 216 = 648 cattle-days. At 6 cattle, the time is 648 cattle-days ÷ 6 cattle = 108 days. The likely mistake is 36 days, which does not account correctly for the three fields and the reduced number of cattle.

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