Free Optics MCQs with Answers
665 Optics MCQs from Physics, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
Light is studied through reflection, refraction, dispersion, interference, diffraction and polarization, linking ray behavior with its wave nature. Questions may involve mirrors, lenses, optical instruments, refractive index and image formation, while geometrical optics deals with rays and wave optics explains effects such as interference and diffraction.
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665 questions · page 16 of 34
- A. More frequency, less wavelength
- B. Less frequency, less wavelength
- C. Less frequency, more wavelength
- D. More frequency, more wavelength
Explanation: In the spectrum of visible light, VIBGYOR, moving towards the right the wavelength increases and frequency decreases as the the two are…
Correct answer: Less frequency, more wavelength- A. Virtual
- B. Erect
- C. Real
- D. Inverted
- E. Both virtual and erect
Explanation: First, the object is closer than the focus - this is a magnifying glass so, the image is erect, enlarged, and virtual.Use lens formula…
Correct answer: Both virtual and erect- A. 300 nm
- B. 400 nm
- C. 600 nm
- D. 900 nm
- E. 950 nm
Explanation: The explanation is given below:The wavelength in the third-order spectrum is 400nm.Where,n₁=initial order of the spectran₂=final order of…
Correct answer: 400 nm- A. I only
- B. II only
- C. III only
- D. II and III only
- E. I, II and III
Explanation: The magnification is defined as the ratio of the size of the image to the size of the object.
Correct answer: I only- A. Magnifying Power of the telescope
- B. Width of the telescope
- C. Length of the telescope
- D. Height of the telescope
- E. Diameter of the lens of the telescope
Explanation: The distance between the eyepiece lens and the objective lens is called the length of the telescope as shown below :
Correct answer: Length of the telescope- A. I only
- B. II only
- C. III only
- D. I and III only
- E. I, II, and III
Explanation: Polarization can be done using:1. Scattering: When light interacts with particles or molecules in a medium, it can be scattered.
Correct answer: I, II, and III- A. The object is 2 cm from the lens
- B. The object is 4 cm from the lens
- C. The object is 6 cm from the lens
- D. The object is 8 cm from the lens
- E. The object is 10 cm from the lens
Explanation: The explanation is given below:f=20cm and v=2uSign convention u=+vev=+vef=+ve1/2u-1/u=1/f 1-2/2u=1/20 -1/2u =-1/20 2u=20 u=10cm So the…
Correct answer: The object is 10 cm from the lens- A. Blue
- B. Violet
- C. Red
- D. Green
Explanation: VIBGYORFrom left to right:Wavelength increases.Frequency decreases.Energy(hf) decreases so energy decreases from violet to red.Maximum…
Correct answer: Violet- A. Balmer series
- B. Pashchen series
- C. Lyman series
- D. Brackett series
Explanation: The Lyman series lies in the UV region.Balmer series lies in the visible region.Paschen series lies in the near IR region.Brackett series…
Correct answer: Lyman series- A. Frequency
- B. Wave length
- C. Energy
- D. Origin
Explanation: The main difference is of the origin. X-rays are emitted by electrons outside the nucleus whereas, the gamma rays are emitted by the…
Correct answer: Origin- A. Diffraction of light waves
- B. Dispersion of light waves
- C. Interference of light waves
- D. Scattering of light waves
Explanation: The bright colors seen in an oil slick floating on water or in a sunlit soap bubble are caused by interference.
Correct answer: Interference of light waves- A. The distance between the objective and focal point of eyepiece
- B. The distance between the object and final image
- C. The distance between the objective and eyepiece
- D. The distance between the focal point of objective and eyepiece
- E. The distance between the eyepiece and final image
Explanation: The length of the telescope is also termed as focal length. Generally expressed, the focal length is the distance (given in millimeters)…
Correct answer: The distance between the objective and eyepiece- A. Coulomb's Law
- B. Bragg's Law
- C. Faraday's Law
- D. Ohm's Law
- E. Gravitational Law
Explanation: The equation of Bragg's Law is mλ=2dsin(θ), where m is the order of the diffraction, λ represents the wavelength of the incident wave, d…
Correct answer: Bragg's Law- A. 20 cm
- B. 25 cm
- C. 33 cm
- D. 50 cm
- E. 100 cm
Explanation: The explanation is given below:u = 25 cmm = -4 [a real image so it must be inverted]v = - m * u = - * (-4) * 25 = 100 cmf = u * v / (u +…
Correct answer: 20 cm- A. I only
- B. II only
- C. III only
- D. I and II only
- E. I, II and III
Explanation: 1. Scattering: When light interacts with particles or molecules in a medium, it can be scattered.
Correct answer: I, II and III- A. Converge at the principal focus
- B. Converge inside the principal focus
- C. Converge outside the principal focus
- D. Converge at the center of curvature
- E. diverge as long as theý are close to the lens
Explanation: Incident rays of light parallel to the principal axis of the convex lens converge at the principal focus.A convex lens also known as a…
Correct answer: Converge at the principal focus- A. 4.6 x 10^7 to 7.8 x 10 -7 m
- B. 4.0 x 10 -7 to 7.6 x 10 -7 m
- C. 4.0 x 10 -6 to 7.6 x 10 -6 m
- D. 4.0 x 10 -8 to 7.6 x 10 -8 m
Explanation: The range of wavelengths of visible light is from 400nm to 760nm.
Correct answer: 4.0 x 10 -7 to 7.6 x 10 -7 m318. In an astronomical telescope, the lens called eyepiece forms an image of a distant object that is:
- A. Real and diminished
- B. Real and magnified
- C. Virtual and diminished
- D. Virtual and magnified
Explanation: An astronomical telescope is an optical instrument which is used to see the magnified image of distant heavenly bodies.
Correct answer: Virtual and magnified- A. 6 cm
- B. 1 m
- C. 80 cm
- D. 4 m
- E. 3 cm
Explanation: The distance from the lens to the image is of 6 cm as focal length is used to photograph at distance.
Correct answer: 6 cm- A. Shadow
- B. Refraction
- C. Diffraction
- D. Reflection
Explanation: The property of light bending around obstacles and the spreading of waves into the geometrical shadow of an obstacle is called…
Correct answer: Diffraction