A parallel beam of white light is incident normally on a diffraction grating. It is noted that the second-order and third-order spectra partially overlap. Which wavelength in the third-order spectrum appears at the same angle as the wavelength of 600 nm in the second-order spectrum?
Correct answer: B. 400 nm
- A. 300 nm
- B. 400 nm
- C. 600 nm
- D. 900 nm
- E. 950 nm
Explanation
The explanation is given below:The wavelength in the third-order spectrum is 400nm.Where,n₁=initial order of the spectran₂=final order of the spectraλ₁=initial wavelength of the spectraλ₂=final wavelength of the spectraFrom the question we have,n₁=2λ₁=600nmn₂=3By substituting the required values in equation (1) we get;Hence, the wavelength in the third-order spectrum is 400nm.
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