Free Electric Field Intensity MCQs with Answers
30 Electric Field Intensity MCQs from Physics, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
Electric field intensity is the force acting per unit positive test charge, with direction set by the force on that charge. Work includes fields of point charges, vector superposition, field lines and the relation between field and electric potential. Field intensity must be distinguished from electric force and potential.
Last updated
30 questions · page 2 of 2
- A. E=O
- B. E < mg / q
- C. E=mg / q
- D. E > mg / q
Explanation: If particle moves with constant velocity, by Newton's laws, net force (ΣF) is zero.
Correct answer: E=mg / q- A. Perpendicular to the direction of field
- B. Opposite to the direction of force
- C. At a certain angle
- D. Along the direction of force
Explanation: Electric intensity, also known as electric field intensity, is the force experienced by a unit positive charge placed at a point in an…
Correct answer: Along the direction of force- A. 1440i+1080jV/m
- B. 1240i+1280jN/C
- C. 1440i+1080jN/C
- D. 1240i+1080jN/C
Explanation: The formula for the electric field strength is E=(K x Charge, Q)/distance2.
Correct answer: 1440i+1080jN/C- A. Volt/meter
- B. Newton/coulomb
- C. Joule/coulomb_meter
- D. All of above
Explanation: Therefore, the correct answer is "All of the above" since all the options are valid units for electric intensity, each expressing a…
Correct answer: All of above- A. 1.6x10^-4
- B. 1.6x10^-8
- C. 1.6x10^-10
- D. 1.6x10^-11
Explanation: The force on an electron in an electric field can be calculated by using the formula:F = qEWhere 'q' is the charge of the electron.
Correct answer: 1.6x10^-11- A. 240 NC-1
- B. 24 NC-1
- C. 2.4 NC-1
- D. 2400 NC-1
Explanation: As we know, Potential gradient is given by E= -dV/dR So, 12/0.005 = 2400 V/m= 2400 N/C
Correct answer: 2400 NC-1- A. Potential energy
- B. Electric field intensity
- C. Electric potential difference
- D. Electron-volt
Explanation: The correct answer is Electric field intensity. The electric field intensity is defined as the negative gradient of electric potential…
Correct answer: Electric field intensity- A. Separation of the plates
- B. Separation and area of the plates
- C. Permittivity of the medium; separation of the plates
- D. Permittivity of the medium; separation and area of the plates
Explanation: The correct answer is Option A: Separation of the plates. The electric field strength between parallel conducting plates can be calculated…
Correct answer: Separation of the plates- A. N/C
- B. V/m
- C. J/C.m
- D. All of the above
Explanation: The units of the electric field in the SI system are newtons per coulomb (N/C), or volts per meter (V/m); in terms of the SI base units…
Correct answer: All of the above- A. Volt/metre
- B. Newton/coulomb
- C. Joule/Coulomb.metre
- D. volt.metre
Explanation: The electric field intensity is defined as the force experienced by a positive test charge divided by the magnitude of the charge.
Correct answer: Newton/coulomb