The force on an electron in the electric field of 10^8 NC^-1 is
Correct answer: D. 1.6x10^-11
- A. 1.6x10^-4
- B. 1.6x10^-8
- C. 1.6x10^-10
- D. 1.6x10^-11
Explanation
The force on an electron in an electric field can be calculated by using the formula:F = qEWhere 'q' is the charge of the electron. The charge of an electron is approximately 1.6 × 10^-19C. Therefore, the force on an electron in an electric field of 10^8 N/C is:F = (1.6 × 10^-19 C) × (10^8 N/C)F = 1.6 × 10^-11 N
This question appeared on the ETEA MDCAT 2010 paper, which you can sit online with every answer explained.
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About Electric Field Intensity
Electric field intensity is the force acting per unit positive test charge, with direction set by the force on that charge. Work includes fields of point charges, vector superposition, field lines and the relation between field and electric potential. Field intensity must be distinguished from electric force and potential.
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